On a question of Mendès France on normal numbers

In 2008 or earlier, Michel Mendès France asked for an instance of a real number $x$ such that both $x$ and $1/x$ are simply normal to a given integer base $b$. We give a positive answer to this question by constructing a number $x$ such that both $x$ and its reciprocal $1/x$ are continued fraction normal as well as normal to all integer bases greater than or equal to $2$. Moreover, $x$ and $1/x$ are computable, the first $n$ digits of their continued fraction expansion can be obtained in $\mathcal{O}(n^4)$ mathematical operations.